Answer :
The answer is option A, 372 kJ. In an isothermal process, the temperature remains constant throughout the process.
The work done by the gas on the piston can be calculated by using the formula of work for a gas: W = nRT ln(V2/V1).
Here, n is the number of moles of gas, R is the universal gas constant, T is the temperature in Kelvin, and V2 and V1 are the final and initial volumes of the gas, respectively.
Using the given values: n = m/M = 2000/32 = 62.5 moles (where m is the mass of O2 gas, and M is the molar mass of O2), R = 8.31 J/mol K, T = 127 + 273 = 400 K, V2 = 60 L, V1 = 10 L
The work done by the gas on the piston is: W = nRT ln(V2/V1)W = 62.5 x 8.31 x 400 ln(60/10)W = 372,097.5 J = 372 kJ
Therefore, the answer is option A, 372 kJ.
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