Answer :
Final answer:
To solve this problem, we need to convert the different volume units to a common unit before subtracting. Converting 9 hL to L, we get 90 L. Subtracting the other volumes, we end up with -90 dL - 5 cL. None of the given options are correct.
Explanation:
The question is asking for the volume measurement of 9 hL (hectoliters) minus 9 dL (decaliters), 4 L (liters), 7 dL, and 5 cL (centiliters). To solve this problem, we need to convert the different units to a common unit before subtracting. 1 hL is equal to 10 L, and 1 L is equal to 10 dL. So if we convert 9 hL to L, we get 9 * 10 = 90 L. Subtracting the other volumes, we have 90 L - 9 dL - 4 L - 7 dL - 5 cL = 90 L - 90 dL - 5 cL = 0 L - 90 dL - 5 cL = -90 dL - 5 cL. Therefore, none of the above options are correct.
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