Answer :
The kinetic energy of a 148 km/h fastball is approximately 33.792% higher than that of a 125 km/h changeup.
The kinetic energy of an object is given by the formula [tex]KE = 1/2 * m * v^2[/tex], where m is the mass of the object and v is its velocity.
To compare the kinetic energy of a fastball and a changeup, we need to determine the difference in their velocities.
The difference in velocities can be calculated by subtracting the velocity of the changeup from the velocity of the fastball.
With the given velocities, the difference in velocities is 148 km/h - 125 km/h = 23 km/h.
To find the percentage difference in kinetic energy, we can use the formula [tex](v1^2 - v2^2) / v2^2 * 100[/tex], where v1 is the velocity of the fastball and v2 is the velocity of the changeup.
Plugging in the values, we get [tex]((148^2 - 125^2) / 125^2) * 100 = 33.792%[/tex]
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