Answer :
Final answer:
To solve the system of linear equations, one must apply methods such as substitution, elimination, or matrix operations. For the quadratic equation provided, the quadratic formula is used, and substituting the values a=1, b=0.0211, and c=-0.0211 provides the solutions for x.
Explanation:
To solve the system of linear equations given by x¹ - 3x² + 4x³ = -4, 3x¹ -7x² +7x³ =-8, and −4x¹+6x²−x³= 7, we can use methods such as substitution, elimination, or matrix operations. However, for the quadratic equation x² +0.0211x -0.0211 = 0, we need to use the quadratic formula, which is given by x = (-b ± √(b² - 4ac)) / (2a). In this case, a = 1, b = 0.0211, and c = -0.0211. Substituting these values into the quadratic formula, we get:
x = (-0.0211 ± √((0.0211)² - 4(1)(-0.0211))) / (2(1))
This calculation will give us the two solutions for x in the quadratic equation.
