College

Solve the following problems:

22. When Mr. Brown began his diet, he weighed 193 lb 7 oz. He now weighs 178 lb 15 oz. How much weight has he lost?

23. Tim Thompson ran a 3-mile run in 20 min 12 sec. George Harris ran the race in 21 min 5 sec. How much longer did it take George to run than Tim?

Answer :

Sure, let's solve each of the problems step-by-step:

Problem 1: Weight Loss of Mr. Brown

Mr. Brown initially weighed 193 pounds and 0.7 ounces. He now weighs 178 pounds and 15 ounces. We need to find out how much weight he has lost.

1. Convert ounces to pounds: Since there are 16 ounces in a pound, we can convert any ounce measurement into a fraction of a pound.
- Initial weight in pounds and ounces: 193 pounds and 0.7 ounces. Convert 0.7 ounces to pounds:
[tex]\(\frac{0.7}{16} = 0.04375\)[/tex] pounds.
- Current weight in pounds and ounces: 178 pounds and 15 ounces. Convert 15 ounces to pounds:
[tex]\(\frac{15}{16} = 0.9375\)[/tex] pounds.

2. Calculate total initial and current weight in pounds:
- Initial total weight: [tex]\(193 + 0.04375 = 193.04375\)[/tex] pounds.
- Current total weight: [tex]\(178 + 0.9375 = 178.9375\)[/tex] pounds.

3. Subtract to find the weight loss:
- Weight lost = Initial total weight - Current total weight
[tex]\[= 193.04375 - 178.9375 = 14.10625\][/tex]

Rounded to three decimal places, Mr. Brown has lost 14.106 pounds.

Problem 2: Time Difference for Running

Tim Thompson completed a 3-mile run in 20 minutes and 12 seconds, whereas George Harris completed it in 21 minutes and 5 seconds. We need to find how much longer it took George compared to Tim.

1. Convert both times entirely to seconds:
- Tim's time: [tex]\(20 \times 60 + 12 = 1200 + 12 = 1212\)[/tex] seconds.
- George's time: [tex]\(21 \times 60 + 5 = 1260 + 5 = 1265\)[/tex] seconds.

2. Calculate the time difference:
- Time George took longer = George's time - Tim's time
[tex]\[= 1265 - 1212 = 53\][/tex] seconds.

3. Convert the time difference back to minutes and seconds:
- Divide 53 by 60 to find whole minutes: [tex]\(53 \div 60 = 0\)[/tex] minutes with a remainder.
- The remainder is 53 seconds.

Thus, George took 0 minutes and 53 seconds longer than Tim to complete the run.