College

Solve [tex]-8x + 40 > -16[/tex]

A. [tex]x < -3[/tex]
B. [tex]x > 7[/tex]
C. [tex]x > -3[/tex]
D. [tex]x < 7[/tex]

Answer :

To solve the inequality [tex]\(-8x + 40 > -16\)[/tex], follow these steps:

1. Move the constant term to the other side:
Start by subtracting 40 from both sides of the inequality:

[tex]\[
-8x + 40 - 40 > -16 - 40
\][/tex]

Simplifying this gives:

[tex]\[
-8x > -56
\][/tex]

2. Solve for [tex]\(x\)[/tex]:
To isolate [tex]\(x\)[/tex], divide both sides of the inequality by [tex]\(-8\)[/tex]. Remember, when you divide or multiply both sides of an inequality by a negative number, you must reverse the inequality sign:

[tex]\[
x < \frac{-56}{-8}
\][/tex]

Simplifying the division:

[tex]\[
x < 7
\][/tex]

Therefore, the solution to the inequality [tex]\(-8x + 40 > -16\)[/tex] is [tex]\(x < 7\)[/tex].

The correct answer is D. [tex]\(x < 7\)[/tex].