High School

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------------------------------------------------ Solve for [tex] x [/tex]:

[tex]
\frac{3x}{6} + 1 = 7
[/tex]

A. [tex] x = 12 [/tex]
B. [tex] x = 16 [/tex]
C. [tex] x = 4 [/tex]

Answer :

To solve the equation [tex]\(\frac{3x}{6} + 1 = 7\)[/tex], we need to find the value of [tex]\(x\)[/tex].

1. Simplify the equation:
Start by isolating the fraction. Subtract 1 from both sides of the equation:
[tex]\[\frac{3x}{6} = 7 - 1\][/tex]
[tex]\[\frac{3x}{6} = 6\][/tex]

2. Simplify the fraction:
The fraction [tex]\(\frac{3x}{6}\)[/tex] can be simplified by dividing both the numerator and the denominator by 3:
[tex]\[\frac{x}{2} = 6\][/tex]

3. Solve for [tex]\(x\)[/tex]:
To get [tex]\(x\)[/tex] by itself, multiply both sides of the equation by 2:
[tex]\[x = 6 \times 2\][/tex]
[tex]\[x = 12\][/tex]

Therefore, the solution to the equation is [tex]\(x = 12\)[/tex]. This matches the option [tex]\(x = 12\)[/tex].