High School

Shanice's school is selling tickets to the annual talent show. On the first day of ticket sales, the school sold 5 senior citizen tickets and 10 child tickets for a total of $110. On the second day, the school took in $101 by selling 10 senior citizen tickets and 3 child tickets. What is the price of one senior citizen ticket and one child ticket?

Answer :

Final answer:

To find the price of one senior citizen ticket and one child ticket, we can set up a system of equations using the information provided. However, upon solving the system, we encounter a negative ticket price, indicating an error in the given information or calculations.

Explanation:

To find the price of one senior citizen ticket and one child ticket, we can set up a system of equations based on the information given.

Let's assume the price of one senior citizen ticket is x dollars and the price of one child ticket is y dollars.

Based on the first day of ticket sales, we can write the equation:

5x + 10y = 110

Based on the second day of ticket sales, we can write the equation:

10x + 3y = 101

Now, we can solve this system of equations to find the values of x and y.

Multiplying the first equation by 3 and the second equation by 10, we can eliminate y by subtracting the two equations:

15x + 30y = 330

10x + 3y = 101

Subtracting the two equations gives us:

5x = 229

Dividing both sides of the equation by 5, we get:

x = 45.8

Substituting the value of x back into either of the original equations, we can solve for y:

5(45.8) + 10y = 110

229 + 10y = 110

10y = -119

y = -11.9

Since we cannot have a negative ticket price, there must be an error in the given information or calculations.

Therefore, the solution to this problem is not possible with the given information.