Answer :
They, at 2000 square feet, both contractors will charge 250,000. To find the cost at this square footage, we can substitute f = 2000 into either of the original equations.
The equation for the cost charged by the first contractor can be represented as:
C1 = 50000 + 100f
The equation for the cost charged by the second contractor can be represented as:
C2 = 70000 + 90f
Now, let's solve the system of equations to find the square footage where the two contractors charge the same amount. We can do this by setting the two equations equal to each other and solving for f:
50000 + 100f = 70000 + 90f
First, let's simplify the equation by combining like terms:
10f = 20000
Next, we'll isolate f by dividing both sides of the equation by 10:
f = 2000
For example, using the equation for the first contractor:
C1 = 50000 + 100(2000)
C1 = 50000 + 200000
C1 = 250000
The, at 2000 square feet, both contractors will charge 250,000.
In conclusion, the system of linear equations that models this problem is:
C1 = 50000 + 100f
C2 = 70000 + 90f
At 2000 square feet, both contractors will charge 250,000.
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