High School

Select the correct product.

\((x^2 + 6x + 9)(3x - 1)\)

A. \(3x^3 + 17x^2 + 21x - 9\)
B. \(3x^3 - 17x^2 - 21x - 9\)
C. \(3x^3 + 19x^2 + 27x + 9\)
D. \(3x^3 + 19x^2 + 9x - 9\)

Answer :

Answer:

3x^3 + 17x^2 + 21x - 9

Step-by-step explanation:

[tex](x^2 + 6x + 9)(3x - 1)[/tex]

Multiply each term in first parenthesis with 3x-1

x^2 times 3x-1 becomes 3x^3 -x^2

6x times 3x-1 becomes 18x^2 -6x

9 times 3x-1 becomes 27x -9

Now we combine like terms

3x^3 -x^2 + 18x^2 -6x + 27x - 9

3x^3 +17x^2 +21x -9
3x^3 + 17x^2 + 21x - 9

this is the correct answer for this problem.

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