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Select the correct answer.

The atomic mass of potassium is 39.1. What is the mass of [tex]$6.02 \times 10^{23}$[/tex] atoms of potassium?

A. [tex]39.1 \, \text{mg}[/tex]
B. [tex]39.1 \, \text{g}[/tex]
C. [tex]39.1 \, \text{kg}[/tex]
D. [tex]6.02 \times 39.1 \, \text{mg}[/tex]
E. [tex]6.02 \times 39.1 \, \text{g}[/tex]

Answer :

To solve the problem, we need to find the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium. Here's how you can approach it:

1. Understand the Relationship with Avogadro's Number:
- Avogadro's number is [tex]\(6.02 \times 10^{23}\)[/tex] atoms/mole. It tells us how many atoms are in one mole of a substance.

2. Given Atomic Mass:
- The atomic mass of potassium is given as 39.1 grams per mole. This means that one mole (or [tex]\(6.02 \times 10^{23}\)[/tex] atoms) of potassium weighs 39.1 grams.

3. Find the Mass for the Given Number of Atoms:
- Since the question exactly asks for the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, this is equivalent to the mass of one mole of potassium.
- Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is 39.1 grams.

4. Select the Correct Option:
- From the choices given, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is 39.1 grams, which corresponds to option B.

So the correct answer is:

B. [tex]\(39.1 \, g\)[/tex]