Answer :
To solve the problem, we need to find the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium. Here's how you can approach it:
1. Understand the Relationship with Avogadro's Number:
- Avogadro's number is [tex]\(6.02 \times 10^{23}\)[/tex] atoms/mole. It tells us how many atoms are in one mole of a substance.
2. Given Atomic Mass:
- The atomic mass of potassium is given as 39.1 grams per mole. This means that one mole (or [tex]\(6.02 \times 10^{23}\)[/tex] atoms) of potassium weighs 39.1 grams.
3. Find the Mass for the Given Number of Atoms:
- Since the question exactly asks for the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, this is equivalent to the mass of one mole of potassium.
- Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is 39.1 grams.
4. Select the Correct Option:
- From the choices given, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is 39.1 grams, which corresponds to option B.
So the correct answer is:
B. [tex]\(39.1 \, g\)[/tex]
1. Understand the Relationship with Avogadro's Number:
- Avogadro's number is [tex]\(6.02 \times 10^{23}\)[/tex] atoms/mole. It tells us how many atoms are in one mole of a substance.
2. Given Atomic Mass:
- The atomic mass of potassium is given as 39.1 grams per mole. This means that one mole (or [tex]\(6.02 \times 10^{23}\)[/tex] atoms) of potassium weighs 39.1 grams.
3. Find the Mass for the Given Number of Atoms:
- Since the question exactly asks for the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, this is equivalent to the mass of one mole of potassium.
- Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is 39.1 grams.
4. Select the Correct Option:
- From the choices given, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is 39.1 grams, which corresponds to option B.
So the correct answer is:
B. [tex]\(39.1 \, g\)[/tex]
