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If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a chance that [tex]\square[/tex] of the offspring will be heterozygous.

[tex]
\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

If the heterozygous [tex]Ww[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is [tex]\square[/tex].

[tex]
\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{array}
\]
[/tex]

Sure! Let's go through each genetic cross step-by-step:

1. First Cross: Heterozygous Male (Ww) with Homozygous Recessive Female (ww)

- The male has the alleles W and w.
- The female has two w alleles.

| Parent Alleles | W | w |
|----------------|----|----|
| w | Ww | ww |
| w | Ww | ww |

- From this table, we can see the possible genotypes of the offspring:
- Ww
- Ww
- ww
- ww

- Out of these four possibilities:
- 2 are heterozygous (Ww)
- 2 are homozygous recessive (ww)

- Therefore, the chance of the offspring being heterozygous (Ww) is 2 out of the 4, or 0.5 (50%).

2. Second Cross: Heterozygous (Ww) with Homozygous Dominant (WW)

- One parent is heterozygous (Ww).
- The other parent is homozygous dominant (WW).

| Parent Alleles | W | w |
|----------------|----|----|
| W | WW | Ww |
| W | WW | Ww |

- From this table, we can see the possible genotypes of the offspring:
- WW
- WW
- Ww
- Ww

- All offspring will either be homozygous dominant (WW) or heterozygous (Ww).
- There are no homozygous recessive (ww) offspring in this cross.

- Therefore, the probability of having a homozygous recessive (ww) offspring is 0 out of the 4, or 0.0 (0%).

These explanations show how the results are obtained for each genetic cross.