Answer :
Let's work through the problem step-by-step to determine the probabilities.
1. First Part: Heterozygous Male (Ww) with Homozygous Recessive Female (ww)
- We are crossing a heterozygous male, Ww, with a homozygous recessive female, ww.
- Create a Punnett square to find the possible genotypes of the offspring:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\][/tex]
- The Punnett square shows the following possible genotypes for the offspring: Ww, ww, Ww, ww.
- Count the number of Ww (heterozygous) genotypes: there are 2 Ww out of 4 total possibilities.
- Calculate the probability: [tex]\(\frac{2}{4} = 0.50\)[/tex] or 50%.
Therefore, there is a 50% chance that the offspring will be heterozygous.
2. Second Part: Heterozygous (Ww) with Homozygous Dominant (WW)
- We are now crossing a heterozygous individual (Ww) with a homozygous dominant individual (WW).
- Create a new Punnett square:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & W \\
\hline
W & WW & WW \\
\hline
w & Ww & Ww \\
\hline
\end{array}
\][/tex]
- The Punnett square shows the following possible genotypes for the offspring: WW, WW, Ww, Ww.
- Notice that there are no ww (homozygous recessive) genotypes in this Punnett square.
- Thus, the probability of homozygous recessive offspring is 0%.
In summary, there is a 50% chance for heterozygous offspring when a Ww individual is crossed with ww, and 0% probability of homozygous recessive offspring when Ww is crossed with WW.
1. First Part: Heterozygous Male (Ww) with Homozygous Recessive Female (ww)
- We are crossing a heterozygous male, Ww, with a homozygous recessive female, ww.
- Create a Punnett square to find the possible genotypes of the offspring:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\][/tex]
- The Punnett square shows the following possible genotypes for the offspring: Ww, ww, Ww, ww.
- Count the number of Ww (heterozygous) genotypes: there are 2 Ww out of 4 total possibilities.
- Calculate the probability: [tex]\(\frac{2}{4} = 0.50\)[/tex] or 50%.
Therefore, there is a 50% chance that the offspring will be heterozygous.
2. Second Part: Heterozygous (Ww) with Homozygous Dominant (WW)
- We are now crossing a heterozygous individual (Ww) with a homozygous dominant individual (WW).
- Create a new Punnett square:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & W \\
\hline
W & WW & WW \\
\hline
w & Ww & Ww \\
\hline
\end{array}
\][/tex]
- The Punnett square shows the following possible genotypes for the offspring: WW, WW, Ww, Ww.
- Notice that there are no ww (homozygous recessive) genotypes in this Punnett square.
- Thus, the probability of homozygous recessive offspring is 0%.
In summary, there is a 50% chance for heterozygous offspring when a Ww individual is crossed with ww, and 0% probability of homozygous recessive offspring when Ww is crossed with WW.
