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If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a [tex]$\square$[/tex] chance that the offspring will be heterozygous.

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

If the heterozygous Ww is crossed with a homozygous dominant WW, then the probability of having a homozygous recessive offspring is [tex]$\square$[/tex].

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & W \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{array}
\]
[/tex]

Let's solve this step-by-step:

Part 1: Mating a heterozygous male (Ww) with a homozygous recessive female (ww)

1. Identify the parents' genotypes:
- Male genotype: Ww
- Female genotype: ww

2. Set up a Punnett Square: Let's determine the possible genotypes of the offspring.

| | W | w |
|---|---|---|
| w | Ww| ww|
| w | Ww| ww|

3. Determine the outcomes:
- The possible offspring genotypes are Ww and ww.

4. Calculate the probability of heterozygous offspring (Ww):
- There are 2 Ww genotypes out of a total of 4 possible genotypes (Ww, Ww, ww, ww).
- Probability = 2/4 = 0.5

So, there is a 0.5 or 50% chance that the offspring will be heterozygous (Ww).

Part 2: Crossing a heterozygous individual (Ww) with a homozygous dominant (WW)

1. Identify the parents' genotypes:
- One parent genotype: Ww
- Other parent genotype: WW

2. Set up a Punnett Square: Let's determine the possible genotypes of the offspring.

| | W | W |
|---|---|---|
| W | WW| WW|
| w | Ww| Ww|

3. Determine the outcomes:
- The possible offspring genotypes are WW and Ww.

4. Calculate the probability of homozygous recessive offspring (ww):
- Since there are no ww offspring from this cross, the probability is 0.

So, the probability of having a homozygous recessive (ww) offspring is 0.

In summary:
- There is a 50% chance of the offspring being heterozygous (Ww) from the first scenario.
- There is a 0% chance of producing a homozygous recessive (ww) offspring from the second scenario.