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If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a chance that [tex]$\square$[/tex] of the offspring will be heterozygous.

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

If the heterozygous Ww is crossed with a homozygous dominant WW, then the probability of having a homozygous recessive offspring is [tex]$\square$[/tex].

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline W & WW & Ww \\
\hline W & WW & Ww \\
\hline
\end{array}
\]
[/tex]

Sure! Let's look at each part of the problem to determine the probabilities for the offspring.

### Part 1: Heterozygous male (Ww) and homozygous recessive female (ww)

1. Genotypes of Parents:
- Male is heterozygous: Ww
- Female is homozygous recessive: ww

2. Possible Offspring:
- We need to find the genotypes of the offspring when Ww is crossed with ww.
- The Punnett square setup is:
```
| | W | w |
|---|---|---|
| w | Ww| ww|
| w | Ww| ww|
```
- The possible genotypes of the offspring are Ww and ww.

3. Probability of Heterozygous Offspring (Ww):
- Out of 4 possible outcomes:
- Ww appears twice.
- So, the probability of having heterozygous offspring is [tex]$\frac{2}{4} = 0.5$[/tex].

### Part 2: Heterozygous (Ww) crossed with homozygous dominant (WW)

1. Genotypes of Parents:
- One parent is heterozygous: Ww
- The other parent is homozygous dominant: WW

2. Possible Offspring:
- We need to find the genotypes of the offspring when Ww is crossed with WW.
- The Punnett square setup is:
```
| | W | w |
|---|---|---|
| W | WW| Ww|
| W | WW| Ww|
```
- The possible genotypes are WW and Ww.

3. Probability of Homozygous Recessive Offspring (ww):
- In these outcomes, there is no ww.
- Hence, the probability of having a homozygous recessive offspring is 0.

In summary:
- There is a 50% (0.5) chance that the offspring from the first mating will be heterozygous (Ww).
- The probability of having a homozygous recessive (ww) offspring from the second mating is 0%.