Answer :
Sure! Let's go through the solution step-by-step for both scenarios presented in the question.
### Scenario 1: Heterozygous Male ([tex]$Ww$[/tex]) with Homozygous Recessive Female ([tex]$ww$[/tex])
When a heterozygous male ([tex]$Ww$[/tex]) is mated with a homozygous recessive female ([tex]$ww$[/tex]), we can use a Punnett square to determine the possible genotypes of the offspring.
- Male Gametes (sperm): W or w
- Female Gametes (eggs): w or w
Now let's fill in the Punnett square:
```
w w
-----------------
W | Ww | Ww |
-----------------
w | ww | ww |
-----------------
```
From this Punnett square, the possible genotypes for the offspring are:
- Two Ww (heterozygous)
- Two ww (homozygous recessive)
Probability of Heterozygous ([tex]$Ww$[/tex]) Offspring:
There are 2 instances of Ww out of a total of 4 possible outcomes. So, the probability of having a heterozygous (Ww) offspring is:
[tex]\[ \text{Probability} = \frac{2}{4} = 0.5 \][/tex]
### Scenario 2: Heterozygous ([tex]$Ww$[/tex]) with Homozygous Dominant ([tex]$WW$[/tex])
In this case, a heterozygous (Ww) individual is crossed with a homozygous dominant (WW) individual.
- First Parent (Ww):
- Gametes: W or w
- Second Parent (WW):
- Gametes: W or W
Let's fill in the Punnett square:
```
W W
-----------------
W | WW | WW |
-----------------
w | Ww | Ww |
-----------------
```
The possible genotypes for the offspring are:
- Two WW (homozygous dominant)
- Two Ww (heterozygous)
Probability of Homozygous Recessive (ww) Offspring:
None of the offspring can be homozygous recessive (ww) because all possible genotypes contain at least one dominant W allele. So, the probability of having a homozygous recessive (ww) offspring is:
[tex]\[ \text{Probability} = 0 \][/tex]
I hope this breakdown helps you understand how these probabilities were determined! If you have any more questions, feel free to ask.
### Scenario 1: Heterozygous Male ([tex]$Ww$[/tex]) with Homozygous Recessive Female ([tex]$ww$[/tex])
When a heterozygous male ([tex]$Ww$[/tex]) is mated with a homozygous recessive female ([tex]$ww$[/tex]), we can use a Punnett square to determine the possible genotypes of the offspring.
- Male Gametes (sperm): W or w
- Female Gametes (eggs): w or w
Now let's fill in the Punnett square:
```
w w
-----------------
W | Ww | Ww |
-----------------
w | ww | ww |
-----------------
```
From this Punnett square, the possible genotypes for the offspring are:
- Two Ww (heterozygous)
- Two ww (homozygous recessive)
Probability of Heterozygous ([tex]$Ww$[/tex]) Offspring:
There are 2 instances of Ww out of a total of 4 possible outcomes. So, the probability of having a heterozygous (Ww) offspring is:
[tex]\[ \text{Probability} = \frac{2}{4} = 0.5 \][/tex]
### Scenario 2: Heterozygous ([tex]$Ww$[/tex]) with Homozygous Dominant ([tex]$WW$[/tex])
In this case, a heterozygous (Ww) individual is crossed with a homozygous dominant (WW) individual.
- First Parent (Ww):
- Gametes: W or w
- Second Parent (WW):
- Gametes: W or W
Let's fill in the Punnett square:
```
W W
-----------------
W | WW | WW |
-----------------
w | Ww | Ww |
-----------------
```
The possible genotypes for the offspring are:
- Two WW (homozygous dominant)
- Two Ww (heterozygous)
Probability of Homozygous Recessive (ww) Offspring:
None of the offspring can be homozygous recessive (ww) because all possible genotypes contain at least one dominant W allele. So, the probability of having a homozygous recessive (ww) offspring is:
[tex]\[ \text{Probability} = 0 \][/tex]
I hope this breakdown helps you understand how these probabilities were determined! If you have any more questions, feel free to ask.
