Answer :
Sure! Let's solve these genetics problems step-by-step using Punnett squares.
### Part 1: Heterozygous Male (Ww) and Homozygous Recessive Female (ww)
Step 1: Set up the Punnett square.
A heterozygous male has the genotype Ww, which means his alleles are W and w. A homozygous recessive female has the genotype ww, which means her alleles are both w.
Here's how the Punnett square looks:
```
| W | w |
--------------------
w | Ww | ww |
--------------------
w | Ww | ww |
```
Step 2: Determine the genotypes of the offspring.
From the Punnett square, the possible offspring genotypes are:
- Two Ww (heterozygous)
- Two ww (homozygous recessive)
Step 3: Calculate the probability of having heterozygous offspring.
Out of 4 possible combinations, 2 are Ww. Therefore, the probability that an offspring is heterozygous is 2 out of 4, which simplifies to:
[tex]\[ \frac{2}{4} = 0.5 \][/tex]
So, there is a 50% chance that the offspring will be heterozygous.
### Part 2: Homozygous Dominant (WW) Crossed with Homozygous Dominant (WW)
Step 1: Set up the Punnett square.
In this cross, both parents are homozygous dominant with genotype WW. So, their alleles are W and W.
Here's how the Punnett square looks:
```
| W | W |
--------------------
W | WW | WW |
--------------------
W | WW | WW |
```
Step 2: Determine the genotypes of the offspring.
From the Punnett square, all offspring genotypes are WW (homozygous dominant).
Step 3: Calculate the probability of having homozygous recessive offspring.
Since all four possible combinations are WW, there are 0 combinations that are homozygous recessive (ww).
Therefore, the probability of having a homozygous recessive offspring is:
[tex]\[ \frac{0}{4} = 0.0 \][/tex]
So, there is a 0% chance of having a homozygous recessive offspring.
### Summary:
- The probability of having a heterozygous offspring when Ww is mated with ww is 0.5 or 50%.
- The probability of having a homozygous recessive offspring when WW is crossed with WW is 0.0 or 0%.
### Part 1: Heterozygous Male (Ww) and Homozygous Recessive Female (ww)
Step 1: Set up the Punnett square.
A heterozygous male has the genotype Ww, which means his alleles are W and w. A homozygous recessive female has the genotype ww, which means her alleles are both w.
Here's how the Punnett square looks:
```
| W | w |
--------------------
w | Ww | ww |
--------------------
w | Ww | ww |
```
Step 2: Determine the genotypes of the offspring.
From the Punnett square, the possible offspring genotypes are:
- Two Ww (heterozygous)
- Two ww (homozygous recessive)
Step 3: Calculate the probability of having heterozygous offspring.
Out of 4 possible combinations, 2 are Ww. Therefore, the probability that an offspring is heterozygous is 2 out of 4, which simplifies to:
[tex]\[ \frac{2}{4} = 0.5 \][/tex]
So, there is a 50% chance that the offspring will be heterozygous.
### Part 2: Homozygous Dominant (WW) Crossed with Homozygous Dominant (WW)
Step 1: Set up the Punnett square.
In this cross, both parents are homozygous dominant with genotype WW. So, their alleles are W and W.
Here's how the Punnett square looks:
```
| W | W |
--------------------
W | WW | WW |
--------------------
W | WW | WW |
```
Step 2: Determine the genotypes of the offspring.
From the Punnett square, all offspring genotypes are WW (homozygous dominant).
Step 3: Calculate the probability of having homozygous recessive offspring.
Since all four possible combinations are WW, there are 0 combinations that are homozygous recessive (ww).
Therefore, the probability of having a homozygous recessive offspring is:
[tex]\[ \frac{0}{4} = 0.0 \][/tex]
So, there is a 0% chance of having a homozygous recessive offspring.
### Summary:
- The probability of having a heterozygous offspring when Ww is mated with ww is 0.5 or 50%.
- The probability of having a homozygous recessive offspring when WW is crossed with WW is 0.0 or 0%.
