Answer :
Sure, let's walk through the solution to this question step by step.
### Step 1: Understanding the First Cross (Ww x ww)
1. Parent Genotypes:
- Heterozygous male: [tex]\( Ww \)[/tex]
- Homozygous recessive female: [tex]\( ww \)[/tex]
2. Possible Gametes:
- Male can produce: [tex]\( W \)[/tex] or [tex]\( w \)[/tex]
- Female can produce: [tex]\( w \)[/tex] or [tex]\( w \)[/tex]
3. Punnett Square:
- The Punnett Square for this cross looks like this:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\][/tex]
4. Offspring Genotypes and Probabilities:
- [tex]\( Ww \)[/tex] (heterozygous): 2 out of 4 possible outcomes
- [tex]\( ww \)[/tex] (homozygous recessive): 2 out of 4 possible outcomes
5. Calculating the Probability of Heterozygous Offspring:
- There are 4 possible outcomes total, and 2 of them are [tex]\( Ww \)[/tex].
- Probability [tex]\( = \frac{2}{4} = \frac{1}{2} = 0.5 \)[/tex]
### Step 2: Understanding the Second Cross (Ww x WW)
1. Parent Genotypes:
- Heterozygous: [tex]\( Ww \)[/tex]
- Homozygous dominant: [tex]\( WW \)[/tex]
2. Possible Gametes:
- Heterozygous parent can produce: [tex]\( W \)[/tex] or [tex]\( w \)[/tex]
- Homozygous dominant parent can produce: [tex]\( W \)[/tex] or [tex]\( W \)[/tex]
3. Punnett Square:
- The Punnett Square for this cross looks like this:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & W \\
\hline W & WW & WW \\
\hline w & Ww & Ww \\
\hline
\end{array}
\][/tex]
4. Offspring Genotypes and Probabilities:
- [tex]\( WW \)[/tex] (homozygous dominant): 2 out of 4 possible outcomes
- [tex]\( Ww \)[/tex] (heterozygous): 2 out of 4 possible outcomes
- [tex]\( ww \)[/tex] (homozygous recessive): 0 out of 4 possible outcomes
5. Calculating the Probability of Homozygous Recessive Offspring:
- There are 4 possible outcomes total, and 0 of them are [tex]\( ww \)[/tex].
- Probability [tex]\( = \frac{0}{4} = 0 \)[/tex]
### Final Answer:
1. Probability of Heterozygous Offspring from the First Cross: [tex]\(0.5\)[/tex]
2. Probability of Homozygous Recessive Offspring from the Second Cross: [tex]\(0.0\)[/tex]
You have successfully solved the problem with these steps!
### Step 1: Understanding the First Cross (Ww x ww)
1. Parent Genotypes:
- Heterozygous male: [tex]\( Ww \)[/tex]
- Homozygous recessive female: [tex]\( ww \)[/tex]
2. Possible Gametes:
- Male can produce: [tex]\( W \)[/tex] or [tex]\( w \)[/tex]
- Female can produce: [tex]\( w \)[/tex] or [tex]\( w \)[/tex]
3. Punnett Square:
- The Punnett Square for this cross looks like this:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\][/tex]
4. Offspring Genotypes and Probabilities:
- [tex]\( Ww \)[/tex] (heterozygous): 2 out of 4 possible outcomes
- [tex]\( ww \)[/tex] (homozygous recessive): 2 out of 4 possible outcomes
5. Calculating the Probability of Heterozygous Offspring:
- There are 4 possible outcomes total, and 2 of them are [tex]\( Ww \)[/tex].
- Probability [tex]\( = \frac{2}{4} = \frac{1}{2} = 0.5 \)[/tex]
### Step 2: Understanding the Second Cross (Ww x WW)
1. Parent Genotypes:
- Heterozygous: [tex]\( Ww \)[/tex]
- Homozygous dominant: [tex]\( WW \)[/tex]
2. Possible Gametes:
- Heterozygous parent can produce: [tex]\( W \)[/tex] or [tex]\( w \)[/tex]
- Homozygous dominant parent can produce: [tex]\( W \)[/tex] or [tex]\( W \)[/tex]
3. Punnett Square:
- The Punnett Square for this cross looks like this:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & W \\
\hline W & WW & WW \\
\hline w & Ww & Ww \\
\hline
\end{array}
\][/tex]
4. Offspring Genotypes and Probabilities:
- [tex]\( WW \)[/tex] (homozygous dominant): 2 out of 4 possible outcomes
- [tex]\( Ww \)[/tex] (heterozygous): 2 out of 4 possible outcomes
- [tex]\( ww \)[/tex] (homozygous recessive): 0 out of 4 possible outcomes
5. Calculating the Probability of Homozygous Recessive Offspring:
- There are 4 possible outcomes total, and 0 of them are [tex]\( ww \)[/tex].
- Probability [tex]\( = \frac{0}{4} = 0 \)[/tex]
### Final Answer:
1. Probability of Heterozygous Offspring from the First Cross: [tex]\(0.5\)[/tex]
2. Probability of Homozygous Recessive Offspring from the Second Cross: [tex]\(0.0\)[/tex]
You have successfully solved the problem with these steps!
