Select the correct answer from each drop-down menu.

If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a chance that of the offspring will be heterozygous.

\[
\begin{tabular}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{tabular}
\]

If the heterozygous [tex]Ww[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is

\[
\begin{tabular}{|c|c|c|}
\hline
\multicolumn{3}{|c|}{ } \\
\hline
& W & W \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{tabular}
\]

Sure, let's walk through the solution to this question step by step.

### Step 1: Understanding the First Cross (Ww x ww)
1. Parent Genotypes:
- Heterozygous male: [tex]\( Ww \)[/tex]
- Homozygous recessive female: [tex]\( ww \)[/tex]

2. Possible Gametes:
- Male can produce: [tex]\( W \)[/tex] or [tex]\( w \)[/tex]
- Female can produce: [tex]\( w \)[/tex] or [tex]\( w \)[/tex]

3. Punnett Square:
- The Punnett Square for this cross looks like this:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\][/tex]

4. Offspring Genotypes and Probabilities:
- [tex]\( Ww \)[/tex] (heterozygous): 2 out of 4 possible outcomes
- [tex]\( ww \)[/tex] (homozygous recessive): 2 out of 4 possible outcomes

5. Calculating the Probability of Heterozygous Offspring:
- There are 4 possible outcomes total, and 2 of them are [tex]\( Ww \)[/tex].
- Probability [tex]\( = \frac{2}{4} = \frac{1}{2} = 0.5 \)[/tex]

### Step 2: Understanding the Second Cross (Ww x WW)
1. Parent Genotypes:
- Heterozygous: [tex]\( Ww \)[/tex]
- Homozygous dominant: [tex]\( WW \)[/tex]

2. Possible Gametes:
- Heterozygous parent can produce: [tex]\( W \)[/tex] or [tex]\( w \)[/tex]
- Homozygous dominant parent can produce: [tex]\( W \)[/tex] or [tex]\( W \)[/tex]

3. Punnett Square:
- The Punnett Square for this cross looks like this:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & W \\
\hline W & WW & WW \\
\hline w & Ww & Ww \\
\hline
\end{array}
\][/tex]

4. Offspring Genotypes and Probabilities:
- [tex]\( WW \)[/tex] (homozygous dominant): 2 out of 4 possible outcomes
- [tex]\( Ww \)[/tex] (heterozygous): 2 out of 4 possible outcomes
- [tex]\( ww \)[/tex] (homozygous recessive): 0 out of 4 possible outcomes

5. Calculating the Probability of Homozygous Recessive Offspring:
- There are 4 possible outcomes total, and 0 of them are [tex]\( ww \)[/tex].
- Probability [tex]\( = \frac{0}{4} = 0 \)[/tex]

### Final Answer:
1. Probability of Heterozygous Offspring from the First Cross: [tex]\(0.5\)[/tex]
2. Probability of Homozygous Recessive Offspring from the Second Cross: [tex]\(0.0\)[/tex]

You have successfully solved the problem with these steps!