Answer :
We start by analyzing each mating separately.
______________________________
1. Crossing a heterozygous male ([tex]$Ww$[/tex]) with a homozygous recessive female ([tex]$ww$[/tex]):
- The male produces two types of gametes: one carrying [tex]$W$[/tex] and the other carrying [tex]$w$[/tex].
- The female produces only one type of gamete: [tex]$w$[/tex].
Now, we list the possible combinations:
[tex]$$
\begin{array}{c|c}
\text{Male Gamete} & \text{Resulting Offspring} \\
\hline
W & W \, (from\, male) \, + \, w \, (from\, female) = Ww \, (\text{heterozygous}) \\
w & w \, (from\, male) \, + \, w \, (from\, female) = ww \, (\text{homozygous recessive})
\end{array}
$$[/tex]
Since there are 2 equally likely outcomes:
- 1 out of 2 offspring (or [tex]$50\%$[/tex]) will be heterozygous ([tex]$Ww$[/tex]).
______________________________
2. Crossing a heterozygous individual ([tex]$Ww$[/tex]) with a homozygous dominant individual ([tex]$WW$[/tex]):
- The heterozygous produces gametes [tex]$W$[/tex] and [tex]$w$[/tex].
- The homozygous dominant produces only gametes containing [tex]$W$[/tex].
Now, we list the potential offspring:
[tex]$$
\begin{array}{c|c}
\text{Gamete from } Ww & \text{Resulting Offspring} \\
\hline
W & W \, (from\, Ww) \, + \, W \, (from\, WW) = WW \, (\text{homozygous dominant}) \\
w & w \, (from\, Ww) \, + \, W \, (from\, WW) = Ww \, (\text{heterozygous})
\end{array}
$$[/tex]
In this cross, there is no possibility of forming an offspring with the genotype [tex]$ww$[/tex] (homozygous recessive).
Thus, the probability of a homozygous recessive offspring is [tex]$0$[/tex].
______________________________
Final Answers:
- For the first cross, [tex]$50\%$[/tex] of the offspring will be heterozygous.
- For the second cross, the probability of having a homozygous recessive offspring is [tex]$0$[/tex].
______________________________
1. Crossing a heterozygous male ([tex]$Ww$[/tex]) with a homozygous recessive female ([tex]$ww$[/tex]):
- The male produces two types of gametes: one carrying [tex]$W$[/tex] and the other carrying [tex]$w$[/tex].
- The female produces only one type of gamete: [tex]$w$[/tex].
Now, we list the possible combinations:
[tex]$$
\begin{array}{c|c}
\text{Male Gamete} & \text{Resulting Offspring} \\
\hline
W & W \, (from\, male) \, + \, w \, (from\, female) = Ww \, (\text{heterozygous}) \\
w & w \, (from\, male) \, + \, w \, (from\, female) = ww \, (\text{homozygous recessive})
\end{array}
$$[/tex]
Since there are 2 equally likely outcomes:
- 1 out of 2 offspring (or [tex]$50\%$[/tex]) will be heterozygous ([tex]$Ww$[/tex]).
______________________________
2. Crossing a heterozygous individual ([tex]$Ww$[/tex]) with a homozygous dominant individual ([tex]$WW$[/tex]):
- The heterozygous produces gametes [tex]$W$[/tex] and [tex]$w$[/tex].
- The homozygous dominant produces only gametes containing [tex]$W$[/tex].
Now, we list the potential offspring:
[tex]$$
\begin{array}{c|c}
\text{Gamete from } Ww & \text{Resulting Offspring} \\
\hline
W & W \, (from\, Ww) \, + \, W \, (from\, WW) = WW \, (\text{homozygous dominant}) \\
w & w \, (from\, Ww) \, + \, W \, (from\, WW) = Ww \, (\text{heterozygous})
\end{array}
$$[/tex]
In this cross, there is no possibility of forming an offspring with the genotype [tex]$ww$[/tex] (homozygous recessive).
Thus, the probability of a homozygous recessive offspring is [tex]$0$[/tex].
______________________________
Final Answers:
- For the first cross, [tex]$50\%$[/tex] of the offspring will be heterozygous.
- For the second cross, the probability of having a homozygous recessive offspring is [tex]$0$[/tex].
