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------------------------------------------------ Select the correct answer from each drop-down menu.

1. If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a chance that [tex]$\square$[/tex] of the offspring will be heterozygous.

[tex]\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\][/tex]

2. If the heterozygous [tex]Ww[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is

[tex]\[
\begin{array}{|c|c|c|}
\hline
& W & W \\
\hline
W & WW & WW \\
\hline
w & Ww & Ww \\
\hline
\end{array}
\][/tex]

Certainly! Let's work through the problem step-by-step for both scenarios.

Scenario 1: Crossing a heterozygous male (Ww) with a homozygous recessive female (ww):

1. We set up a Punnett square to visualize the possible genetic combinations. The male (Ww) has two alleles: W and w. The female (ww) has two alleles, both being w.

2. In the Punnett square, we combine each allele from the male with each allele from the female:

```
| W | w |
-----------------
w | Ww | ww |
-----------------
w | Ww | ww |
```

3. The offspring possibilities are:
- 50% chance of being Ww (heterozygous)
- 50% chance of being ww (homozygous recessive)

So, there is a 50% chance that the offspring will be heterozygous (Ww).

Scenario 2: Crossing a heterozygous (Ww) with a homozygous dominant (WW):

1. Here, the male (Ww) has alleles W and w, and the homozygous dominant (WW) has two alleles, both being W.

2. We create a Punnett square for this cross:

```
| W | W |
--------------------
W | WW | WW |
--------------------
w | Ww | Ww |
```

3. The offspring possibilities are:
- 50% chance of being WW (homozygous dominant)
- 50% chance of being Ww (heterozygous)

In this scenario, there is 0% chance of having homozygous recessive (ww) offspring.

Combining the results:
- The chance of offspring being heterozygous in the first scenario is 50%.
- The chance of having a homozygous recessive offspring in the second scenario is 0%.