Answer :
Certainly! Let's work through the problem step-by-step for both scenarios.
Scenario 1: Crossing a heterozygous male (Ww) with a homozygous recessive female (ww):
1. We set up a Punnett square to visualize the possible genetic combinations. The male (Ww) has two alleles: W and w. The female (ww) has two alleles, both being w.
2. In the Punnett square, we combine each allele from the male with each allele from the female:
```
| W | w |
-----------------
w | Ww | ww |
-----------------
w | Ww | ww |
```
3. The offspring possibilities are:
- 50% chance of being Ww (heterozygous)
- 50% chance of being ww (homozygous recessive)
So, there is a 50% chance that the offspring will be heterozygous (Ww).
Scenario 2: Crossing a heterozygous (Ww) with a homozygous dominant (WW):
1. Here, the male (Ww) has alleles W and w, and the homozygous dominant (WW) has two alleles, both being W.
2. We create a Punnett square for this cross:
```
| W | W |
--------------------
W | WW | WW |
--------------------
w | Ww | Ww |
```
3. The offspring possibilities are:
- 50% chance of being WW (homozygous dominant)
- 50% chance of being Ww (heterozygous)
In this scenario, there is 0% chance of having homozygous recessive (ww) offspring.
Combining the results:
- The chance of offspring being heterozygous in the first scenario is 50%.
- The chance of having a homozygous recessive offspring in the second scenario is 0%.
Scenario 1: Crossing a heterozygous male (Ww) with a homozygous recessive female (ww):
1. We set up a Punnett square to visualize the possible genetic combinations. The male (Ww) has two alleles: W and w. The female (ww) has two alleles, both being w.
2. In the Punnett square, we combine each allele from the male with each allele from the female:
```
| W | w |
-----------------
w | Ww | ww |
-----------------
w | Ww | ww |
```
3. The offspring possibilities are:
- 50% chance of being Ww (heterozygous)
- 50% chance of being ww (homozygous recessive)
So, there is a 50% chance that the offspring will be heterozygous (Ww).
Scenario 2: Crossing a heterozygous (Ww) with a homozygous dominant (WW):
1. Here, the male (Ww) has alleles W and w, and the homozygous dominant (WW) has two alleles, both being W.
2. We create a Punnett square for this cross:
```
| W | W |
--------------------
W | WW | WW |
--------------------
w | Ww | Ww |
```
3. The offspring possibilities are:
- 50% chance of being WW (homozygous dominant)
- 50% chance of being Ww (heterozygous)
In this scenario, there is 0% chance of having homozygous recessive (ww) offspring.
Combining the results:
- The chance of offspring being heterozygous in the first scenario is 50%.
- The chance of having a homozygous recessive offspring in the second scenario is 0%.
