Answer :
Let's tackle the problem step by step:
1. Crossing a Heterozygous Male with a Homozygous Recessive Female:
- The male has the genotype Ww, meaning he has one dominant allele (W) and one recessive allele (w).
- The female is homozygous recessive with a genotype of ww, meaning she has two recessive alleles (w and w).
We can use a Punnett square to determine the potential genotypes of their offspring:
```
| | W | w |
|---|-----|-----|
| w | Ww | ww |
| w | Ww | ww |
```
From the Punnett square, we can see the possible genotypes of the offspring:
- Two boxes (Ww) represent heterozygous offspring.
- Two boxes (ww) represent homozygous recessive offspring.
So, there is a chance that 2 out of the 4 possible combinations will result in heterozygous offspring. This means 50% or 0.5 of the offspring will be heterozygous.
2. Crossing a Heterozygous Individual (WW) with a Homozygous Dominant (WW):
- WW indicates the genotype where both alleles are dominant.
- Since both parents have the genes WW, their offspring's possible genotypes are determined as follows:
```
| | W | W |
|---|-----|-----|
| W | WW | WW |
| W | WW | WW |
```
Here, all possible combinations (WW) are homozygous dominant. There are no homozygous recessive (ww) combinations possible from this cross.
Therefore, the probability of having a homozygous recessive offspring is 0.
In conclusion, when a heterozygous male (Ww) mates with a homozygous recessive female (ww), 50% of the offspring will be heterozygous (Ww). Similarly, when a homozygous dominant individual (WW) is crossed with another homozygous dominant (WW), there is a 0% chance of producing homozygous recessive offspring.
1. Crossing a Heterozygous Male with a Homozygous Recessive Female:
- The male has the genotype Ww, meaning he has one dominant allele (W) and one recessive allele (w).
- The female is homozygous recessive with a genotype of ww, meaning she has two recessive alleles (w and w).
We can use a Punnett square to determine the potential genotypes of their offspring:
```
| | W | w |
|---|-----|-----|
| w | Ww | ww |
| w | Ww | ww |
```
From the Punnett square, we can see the possible genotypes of the offspring:
- Two boxes (Ww) represent heterozygous offspring.
- Two boxes (ww) represent homozygous recessive offspring.
So, there is a chance that 2 out of the 4 possible combinations will result in heterozygous offspring. This means 50% or 0.5 of the offspring will be heterozygous.
2. Crossing a Heterozygous Individual (WW) with a Homozygous Dominant (WW):
- WW indicates the genotype where both alleles are dominant.
- Since both parents have the genes WW, their offspring's possible genotypes are determined as follows:
```
| | W | W |
|---|-----|-----|
| W | WW | WW |
| W | WW | WW |
```
Here, all possible combinations (WW) are homozygous dominant. There are no homozygous recessive (ww) combinations possible from this cross.
Therefore, the probability of having a homozygous recessive offspring is 0.
In conclusion, when a heterozygous male (Ww) mates with a homozygous recessive female (ww), 50% of the offspring will be heterozygous (Ww). Similarly, when a homozygous dominant individual (WW) is crossed with another homozygous dominant (WW), there is a 0% chance of producing homozygous recessive offspring.
