Answer :
Certainly! Let's go through the problem step-by-step.
1. Mating a Heterozygous Male (Ww) with a Homozygous Recessive Female (ww):
To understand the possible genotypes of the offspring, we'll set up a Punnett square. This is a tool used in genetics to determine the probability of an offspring having a particular genotype.
- The heterozygous male has a genotype of Ww, which means he can pass on either the W or the w allele.
- The homozygous recessive female has a genotype of ww, so she can only pass on the w allele.
The Punnett square for this cross looks like this:
[tex]\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\][/tex]
- The possible genotypes for the offspring are Ww, Ww, ww, and ww.
- Out of the 4 possible outcomes, 2 of them are heterozygous (Ww).
Therefore, there is a 50% chance that the offspring will be heterozygous (Ww).
2. Crossing Heterozygous (Ww) with Homozygous Dominant (WW):
Now, let's consider the cross between a heterozygous individual (Ww) and a homozygous dominant individual (WW).
- The heterozygous individual (Ww) can pass either the W or w allele.
- The homozygous dominant individual (WW) can only pass the W allele.
The Punnett square for this cross looks like this:
[tex]\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{array}
\][/tex]
- The possible genotypes for the offspring are WW, WW, Ww, and Ww.
- None of these outcomes are homozygous recessive (ww).
Therefore, there is a 0% chance of having a homozygous recessive (ww) offspring in this scenario.
In summary:
- When a heterozygous male (Ww) is mated with a homozygous recessive female (ww), there is a 50% chance of having heterozygous offspring.
- When a heterozygous individual (Ww) is crossed with a homozygous dominant individual (WW), there is a 0% chance of having homozygous recessive offspring.
1. Mating a Heterozygous Male (Ww) with a Homozygous Recessive Female (ww):
To understand the possible genotypes of the offspring, we'll set up a Punnett square. This is a tool used in genetics to determine the probability of an offspring having a particular genotype.
- The heterozygous male has a genotype of Ww, which means he can pass on either the W or the w allele.
- The homozygous recessive female has a genotype of ww, so she can only pass on the w allele.
The Punnett square for this cross looks like this:
[tex]\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\][/tex]
- The possible genotypes for the offspring are Ww, Ww, ww, and ww.
- Out of the 4 possible outcomes, 2 of them are heterozygous (Ww).
Therefore, there is a 50% chance that the offspring will be heterozygous (Ww).
2. Crossing Heterozygous (Ww) with Homozygous Dominant (WW):
Now, let's consider the cross between a heterozygous individual (Ww) and a homozygous dominant individual (WW).
- The heterozygous individual (Ww) can pass either the W or w allele.
- The homozygous dominant individual (WW) can only pass the W allele.
The Punnett square for this cross looks like this:
[tex]\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{array}
\][/tex]
- The possible genotypes for the offspring are WW, WW, Ww, and Ww.
- None of these outcomes are homozygous recessive (ww).
Therefore, there is a 0% chance of having a homozygous recessive (ww) offspring in this scenario.
In summary:
- When a heterozygous male (Ww) is mated with a homozygous recessive female (ww), there is a 50% chance of having heterozygous offspring.
- When a heterozygous individual (Ww) is crossed with a homozygous dominant individual (WW), there is a 0% chance of having homozygous recessive offspring.
