Select the correct answer from each drop-down menu.

1. If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a chance that [tex]\(\vee\)[/tex] of the offspring will be heterozygous.

[tex]\[
\begin{tabular}{|c|c|c|}
\hline
\multicolumn{3}{|c|}{} \\
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{tabular}
\][/tex]

2. If the heterozygous Ww is crossed with a homozygous dominant WW, then the probability of having a homozygous recessive offspring is [tex]\(\square\)[/tex].

[tex]\[
\begin{tabular}{|c|c|c|}
\hline
& W & w \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{tabular}
\][/tex]

If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a chance that 50% of the offspring will be heterozygous.

If the heterozygous Ww is crossed with a homozygous dominant WW, then the probability of having a homozygous recessive offspring is 0%.

Explanation:

Heterozygous male (Ww) x Homozygous recessive female (ww):

The possible offspring genotypes are:

Ww (heterozygous) from W (father) and w (mother)

ww (homozygous recessive) from w (father) and w (mother)

The probability of offspring being heterozygous (Ww) is 50% because half of the possible combinations are Ww.

Heterozygous (Ww) x Homozygous dominant (WW):

The possible offspring genotypes are:

WW (homozygous dominant) from W (father) and W (mother)

Ww (heterozygous) from W (father) and w (mother)

Since neither combination results in a homozygous recessive (ww) offspring, the probability of having a homozygous recessive offspring is 0%.