Answer :
Sure! Let's go through the question step-by-step to understand how we arrive at the answer.
1. First Scenario: Heterozygous Male (Ww) x Homozygous Recessive Female (ww)
- Parents' Genotypes: The male has the genotype Ww, which means he has one dominant allele (W) and one recessive allele (w). The female is homozygous recessive, so her genotype is ww, with two recessive alleles.
- Punnett Square Setup:
| | W | w |
|---|---|---|
| w | Ww | ww |
| w | Ww | ww |
The Punnett square shows that there are four possible combinations of alleles for the offspring:
- Ww
- Ww
- ww
- ww
- Result: Out of these four combinations, two are heterozygous (Ww). Therefore, there is a 2 out of 4, or 50% chance that the offspring will be heterozygous.
2. Second Scenario: Heterozygous (Ww) x Homozygous Dominant (WW)
- Parents' Genotypes: Here, we're crossing a heterozygous (Ww) with a homozygous dominant (WW), meaning both alleles in the second parent's genes are dominant.
- Punnett Square Setup:
| | W | W |
|---|---|---|
| W | WW | WW |
| w | Ww | Ww |
For this scenario, the possible offspring genotypes are:
- WW
- WW
- Ww
- Ww
- Result: None of the offspring will be homozygous recessive (ww), as shown in the Punnett square. This means there is a 0% chance of having a homozygous recessive offspring.
Therefore, the correct answers are:
- There is a 50% chance that the offspring will be heterozygous when a heterozygous male (Ww) is crossed with a homozygous recessive female (ww).
- There is a 0% chance of having a homozygous recessive offspring when a heterozygous (Ww) is crossed with a homozygous dominant (WW).
1. First Scenario: Heterozygous Male (Ww) x Homozygous Recessive Female (ww)
- Parents' Genotypes: The male has the genotype Ww, which means he has one dominant allele (W) and one recessive allele (w). The female is homozygous recessive, so her genotype is ww, with two recessive alleles.
- Punnett Square Setup:
| | W | w |
|---|---|---|
| w | Ww | ww |
| w | Ww | ww |
The Punnett square shows that there are four possible combinations of alleles for the offspring:
- Ww
- Ww
- ww
- ww
- Result: Out of these four combinations, two are heterozygous (Ww). Therefore, there is a 2 out of 4, or 50% chance that the offspring will be heterozygous.
2. Second Scenario: Heterozygous (Ww) x Homozygous Dominant (WW)
- Parents' Genotypes: Here, we're crossing a heterozygous (Ww) with a homozygous dominant (WW), meaning both alleles in the second parent's genes are dominant.
- Punnett Square Setup:
| | W | W |
|---|---|---|
| W | WW | WW |
| w | Ww | Ww |
For this scenario, the possible offspring genotypes are:
- WW
- WW
- Ww
- Ww
- Result: None of the offspring will be homozygous recessive (ww), as shown in the Punnett square. This means there is a 0% chance of having a homozygous recessive offspring.
Therefore, the correct answers are:
- There is a 50% chance that the offspring will be heterozygous when a heterozygous male (Ww) is crossed with a homozygous recessive female (ww).
- There is a 0% chance of having a homozygous recessive offspring when a heterozygous (Ww) is crossed with a homozygous dominant (WW).
