High School

Select the correct answer from each drop-down menu.

1. If a heterozygous male with the genotype [tex]\(Ww\)[/tex] is mated with a homozygous recessive female of genotype [tex]\(ww\)[/tex], there is a [tex]\(\square\)[/tex] chance that the offspring will be heterozygous.

[tex]\[

\begin{array}{|c|c|c|}

\hline & W & w \\

\hline w & Ww & ww \\

\hline w & Ww & ww \\

\hline

\end{array}

\][/tex]

2. If the heterozygous [tex]\(Ww\)[/tex] is crossed with a homozygous dominant [tex]\(WW\)[/tex], then the probability of having a homozygous recessive offspring is [tex]\(\square\)[/tex].

[tex]\[

\begin{array}{|c|c|c|}

\hline & W & w \\

\hline W & WW & Ww \\

\hline W & WW & Ww \\

\hline

\end{array}

\][/tex]

Answer :

Let's solve the question step-by-step:

1. First Cross: Heterozygous Male (Ww) x Homozygous Recessive Female (ww)

In this genetic cross, we have one parent with the genotype Ww and the other with ww. We can use a Punnett square to determine the probability of different offspring genotypes.

| | W | w |
|------|-----|-----|
| w | Ww | ww |
| w | Ww | ww |

From the Punnett square:

- Two of the four possible offspring (Ww) are heterozygous.
- Two of the four possible offspring (ww) are homozygous recessive.

Therefore, the chance that the offspring will be heterozygous (Ww) is 2 out of 4, which simplifies to a probability of 0.5 or 50%.

2. Second Cross: Heterozygous (Ww) x Homozygous Dominant (WW)

In this cross, we have one parent with the genotype Ww and the other with WW. We use a Punnett square again:

| | W | w |
|------|-----|-----|
| W | WW | Ww |
| W | WW | Ww |

From the Punnett square:

- Two of the four possible offspring (WW) are homozygous dominant.
- Two of the four possible offspring (Ww) are heterozygous.

There are no homozygous recessive offspring (ww) in this case.

Therefore, the probability of having a homozygous recessive offspring (ww) is 0 or 0%.

In summary:
- For the first cross (Ww x ww), the chance of having heterozygous offspring is 0.5 or 50%.
- For the second cross (Ww x WW), the probability of having homozygous recessive offspring is 0.