College

Select the correct answer from each drop-down menu.

1. If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a chance that [tex]\square[/tex] of the offspring will be heterozygous.

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

2. If the heterozygous [tex]Ww[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is [tex]\square[/tex].

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline W & WW & Ww \\
\hline W & WW & Ww \\
\hline
\end{array}
\]
[/tex]

Answer :

Let's break down the problem and find the solutions step-by-step.

First Scenario: Heterozygous Male (Ww) and Homozygous Recessive Female (ww)

1. Parental Genotypes:
- Male: Ww
- Female: ww

2. Determine Possible Offspring Genotypes:
- We need to determine what genotypes are possible when these two are mated. Using a Punnett square, you place the alleles of one parent across the top and the other parent down the side.

```
| W | w |
--------------
w | Ww | ww |
w | Ww | ww |
```

3. Analyze the Offspring:
- Possible genotypes: Ww, ww, Ww, ww
- Offspring genotypes are 2 Ww and 2 ww, making a total of 4.

4. Calculate Probability of Heterozygous Offspring (Ww):
- There are 2 Ww (heterozygous) out of 4 total offspring.
- Probability = Number of Ww offspring / Total number of offspring = 2/4 = 0.5

So, 0.5 (or 50%) of the offspring will be heterozygous.

Second Scenario: Heterozygous (Ww) crossed with Homozygous Dominant (WW)

1. Parental Genotypes:
- One parent is Ww.
- The other parent is WW.

2. Determine Possible Offspring Genotypes:
- Similar to above, use a Punnett square:

```
| W | w |
--------------
W | WW | Ww |
W | WW | Ww |
```

3. Analyze the Offspring:
- Possible genotypes: WW, Ww, WW, Ww
- Offspring genotypes are 2 WW and 2 Ww, making a total of 4.

4. Calculate Probability of Homozygous Recessive Offspring (ww):
- There are 0 ww (homozygous recessive) out of 4 total offspring since all offspring have at least one W.
- Probability = Number of ww offspring / Total number of offspring = 0/4 = 0.0

Therefore, the probability of having a homozygous recessive offspring is 0.0 (or 0%).

These are the probabilities for each scenario based on the Punnett square analysis.

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