Answer :
Let's solve the problem by creating and solving a linear equation.
We are given that there is a balance beam with circles and a square shown evenly balanced. Our task is to create and solve an equation that represents this balance.
From the options provided, let's consider the equation:
[tex]\[ x + 7 = 12 \][/tex]
This equation suggests that the weight of one side, represented by [tex]\( x + 7 \)[/tex], is equal to the weight on the other side, which is 12.
To find the value of [tex]\( x \)[/tex], we need to solve the equation:
1. Start with the equation:
[tex]\[ x + 7 = 12 \][/tex]
2. To isolate [tex]\( x \)[/tex], subtract 7 from both sides of the equation:
[tex]\[ x + 7 - 7 = 12 - 7 \][/tex]
3. Simplifying both sides gives us:
[tex]\[ x = 5 \][/tex]
Therefore, the solution to the equation is [tex]\( x = 5 \)[/tex]. This indicates the value where the balance is perfectly maintained on both sides of the equation.
We are given that there is a balance beam with circles and a square shown evenly balanced. Our task is to create and solve an equation that represents this balance.
From the options provided, let's consider the equation:
[tex]\[ x + 7 = 12 \][/tex]
This equation suggests that the weight of one side, represented by [tex]\( x + 7 \)[/tex], is equal to the weight on the other side, which is 12.
To find the value of [tex]\( x \)[/tex], we need to solve the equation:
1. Start with the equation:
[tex]\[ x + 7 = 12 \][/tex]
2. To isolate [tex]\( x \)[/tex], subtract 7 from both sides of the equation:
[tex]\[ x + 7 - 7 = 12 - 7 \][/tex]
3. Simplifying both sides gives us:
[tex]\[ x = 5 \][/tex]
Therefore, the solution to the equation is [tex]\( x = 5 \)[/tex]. This indicates the value where the balance is perfectly maintained on both sides of the equation.
