High School

Select the correct answer.

Create and solve a linear equation that represents the model, where circles and a square are shown evenly balanced on a balance beam.

A. [tex]x + 5 = 7; \, x = 2[/tex]
B. [tex]x + 7 = 5; \, x = -2[/tex]
C. [tex]x = 5 + 7; \, x = 12[/tex]
D. [tex]x + 7 = 12; \, x = 5[/tex]

Answer :

Sure! Let's go through each of the equations step by step to find which one is correct.

1. Equation: [tex]\( x + 5 = 7 \)[/tex]
- To solve for [tex]\( x \)[/tex], we need to isolate [tex]\( x \)[/tex].
- Subtract 5 from both sides:
[tex]\[
x + 5 - 5 = 7 - 5
\][/tex]
- Simplifying this, we get:
[tex]\[
x = 2
\][/tex]
- Thus, the solution is [tex]\( x = 2 \)[/tex].

2. Equation: [tex]\( x + 7 = 5 \)[/tex]
- To solve for [tex]\( x \)[/tex], we need to isolate [tex]\( x \)[/tex].
- Subtract 7 from both sides:
[tex]\[
x + 7 - 7 = 5 - 7
\][/tex]
- Simplifying this, we get:
[tex]\[
x = -2
\][/tex]
- Thus, the solution is [tex]\( x = -2 \)[/tex].

3. Equation: [tex]\( x = 5 + 7 \)[/tex]
- This is already in a solved form, so let's simplify the right-hand side:
[tex]\[
x = 12
\][/tex]
- Thus, the solution is [tex]\( x = 12 \)[/tex].

4. Equation: [tex]\( x + 7 = 12 \)[/tex]
- To solve for [tex]\( x \)[/tex], we need to isolate [tex]\( x \)[/tex].
- Subtract 7 from both sides:
[tex]\[
x + 7 - 7 = 12 - 7
\][/tex]
- Simplifying this, we get:
[tex]\[
x = 5
\][/tex]
- Thus, the solution is [tex]\( x = 5 \)[/tex].

The correct linear equations and their respective solutions are:
1. [tex]\( x + 5 = 7 \)[/tex] with [tex]\( x = 2 \)[/tex]
2. [tex]\( x + 7 = 5 \)[/tex] with [tex]\( x = -2 \)[/tex]
3. [tex]\( x = 5 + 7 \)[/tex] with [tex]\( x = 12 \)[/tex]
4. [tex]\( x + 7 = 12 \)[/tex] with [tex]\( x = 5 \)[/tex]

Therefore, the linear equation that represents the model and is correctly solved is:

[tex]\[ x + 7 = 12 ; x = 5 \][/tex]
Create and solve a linear equation that represents the model where circle and square are shown evenly balanced on a balance beam. A.x+5=7;x=2