Select the correct answer.

A restaurant has a total of 60 tables. Of those tables, 38 are round, and 13 are located by the window. There are 6 round tables by the window. If tables are randomly assigned to customers, what is the probability that a customer will be seated at a round table or by the window?

A. [tex]\frac{41}{60}[/tex]
B. [tex]\frac{47}{60}[/tex]
C. [tex]\frac{29}{60}[/tex]
D. [tex]\frac{45}{60}[/tex]

To find the probability that a customer will be seated at a round table or by the window, we can use the formula for the probability of either-or events:

[tex]\[ \text{P(A or B)} = \text{P(A)} + \text{P(B)} - \text{P(A and B)} \][/tex]

where:
- P(A) is the probability of a table being round.
- P(B) is the probability of a table being by the window.
- P(A and B) is the probability of a table being both round and by the window.

Let's find each probability:

1. Total Number of Tables: 60

2. Number of Round Tables (P(A)): 38 out of 60 tables are round.

3. Number of Tables by the Window (P(B)): 13 out of 60 tables are by the window.

4. Number of Round Tables by the Window (P(A and B)): 6 tables are both round and by the window.

Now, plug these values into the formula:

[tex]\[ \text{P(round or window)} = \frac{38}{60} + \frac{13}{60} - \frac{6}{60} \][/tex]

[tex]\[ = \frac{38 + 13 - 6}{60} \][/tex]

[tex]\[ = \frac{45}{60} \][/tex]

So, the probability that a customer will be seated at a round table or by the window is [tex]$\frac{45}{60}$[/tex], which simplifies to 0.75. Therefore, the correct answer is:

D. [tex]$\frac{45}{60}$[/tex]