High School

Prof. J.C. Cruz is to receive 4 mEq of sodium chloride per kg of body weight. If she weighs 165 lbs, how many mL of normal saline solution (NSS) should be administered? (NaCl molecular weight = 58.5)

A. 975 mL
B. 1950 mL
C. 3900 mL
D. 2000 mL

Answer :

Final Answer:

Prof. J.C. Cruz should be administered 1950mL of Normal Saline Solution (NSS) (B),

Explanation:

To calculate the amount of Normal Saline Solution (NSS) that Prof. J.C. Cruz should be administered, you can follow these steps:

1. Convert body weight from pounds (lbs) to kilograms (kg):

Body weight in kg = Body weight in lbs / 2.2046

Body weight in kg = 165 lbs / 2.2046 ≈ 74.84 kg

2. Calculate the total mEq of sodium chloride (NaCl) needed:

Total mEq = Body weight in kg * 4 mEq/kg

Total mEq = 74.84 kg * 4 mEq/kg = 299.36 mEq

3. Calculate the volume (mL) of NSS needed:

Volume (mL) = Total mEq / Concentration (mEq/mL)

Volume (mL) = 299.36 mEq / 0.154 mEq/mL (since NaCl has a molecular weight of 58.5 g/mol, and 1 g of NaCl is approximately 0.154 mEq)

Volume (mL) ≈ 1942.07 mL

Rounded to the nearest 10 mL, Prof. J.C. Cruz should be administered 1950 mL of NSS (B).

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