Answer :
To solve the problem of dividing 181 by 7, you can follow these steps:
1. Set up the division: Place 181 under the long division symbol, with 7 as the divisor.
2. Divide: Start by seeing how many times 7 can fit into the first digit or set of digits:
- Look at the first digit of 181, which is 1. Since 7 is greater than 1, move to the first two digits, which is 18.
- Determine how many times 7 fits into 18. It fits 2 times because [tex]\(7 \times 2 = 14\)[/tex], which is less than 18.
3. Subtract: Subtract the result of [tex]\(7 \times 2 = 14\)[/tex] from 18, which leaves a remainder of 4.
4. Bring down the next digit: Bring down the next digit, which is 1, to make the new number 41.
5. Repeat division: Determine how many times 7 fits into 41:
- 7 goes into 41 a total of 5 times since [tex]\(7 \times 5 = 35\)[/tex], which is the largest multiple of 7 under 41.
6. Subtract: Subtract 35 from 41 to get the new remainder of 6.
So, the result of [tex]\(181 \div 7\)[/tex] is a quotient of 25 with a remainder of 6.
1. Set up the division: Place 181 under the long division symbol, with 7 as the divisor.
2. Divide: Start by seeing how many times 7 can fit into the first digit or set of digits:
- Look at the first digit of 181, which is 1. Since 7 is greater than 1, move to the first two digits, which is 18.
- Determine how many times 7 fits into 18. It fits 2 times because [tex]\(7 \times 2 = 14\)[/tex], which is less than 18.
3. Subtract: Subtract the result of [tex]\(7 \times 2 = 14\)[/tex] from 18, which leaves a remainder of 4.
4. Bring down the next digit: Bring down the next digit, which is 1, to make the new number 41.
5. Repeat division: Determine how many times 7 fits into 41:
- 7 goes into 41 a total of 5 times since [tex]\(7 \times 5 = 35\)[/tex], which is the largest multiple of 7 under 41.
6. Subtract: Subtract 35 from 41 to get the new remainder of 6.
So, the result of [tex]\(181 \div 7\)[/tex] is a quotient of 25 with a remainder of 6.
