Answer :

To solve the division problem [tex]\( 2 \div 157 \)[/tex] using long division, follow these steps:

1. Set up the problem: Write 157 inside the division bracket (the dividend) and 2 outside (the divisor).

2. Divide: Begin with the leftmost digit of the dividend. Ask how many times 2 can go into the first digit of 157, which is 1. Since 2 does not go into 1, move to the next digit.

3. Consider the first two digits: Now consider 15 (the first two digits of 157). How many times can 2 fit into 15? It fits 7 times since [tex]\(2 \times 7 = 14\)[/tex].

4. Subtract and bring down the next digit: Subtract 14 from 15, which leaves a remainder of 1. Bring down the next digit from the dividend, which is 7, making it 17.

5. Continue the division: Now determine how many times 2 can go into 17. 2 fits into 17 eight times since [tex]\(2 \times 8 = 16\)[/tex].

6. Subtract and find the remainder: Subtract 16 from 17, which leaves a remainder of 1.

The quotient is 78, and the remainder is 1.

Thus, when you divide 157 by 2, you get a quotient of 78 with a remainder of 1. This can be expressed as:
[tex]\[ 157 \div 2 = 78 \text{ remainder } 1 \][/tex]