Answer :
The distance between Pedro's score and the average LSAT score is: 0.804
How to find the z-score?
A Z-score is a statistical score that represents the position of a raw score in terms of distance from the mean, measured in units of standard deviation.
A Z-score is considered positive if the value is above the mean and negative if the value is below the mean.
The Z-score formula is:
z = (x - μ)/σ
where:
x is the raw value.
μ is the population mean.
σ is the population standard deviation.
Get the parameters like this:
x = 159
μ = 151
σ = 9.95
therefore:
z = (159 - 151)/9.95
z = 0.804
Read more about z-score at: https://brainly.com/question/25638875
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Complete Question is:
Pedro is studying for the LSAT (law school admissions test). The average LSAT score is 151 with a standard deviation of 9.95.
a. Pedro's practice exam score was 159. What is the distance between Pedro's score and the average LSAT score?
Pedro's practice exam score of 159 is 8 points above the average LSAT score of 151.
To find the distance between Pedro's score and the average score, we subtract the average score from Pedro's score:
Pedro's score: 159
Average LSAT score: 151
Standard deviation: 9.95
Distance from the mean = Pedro's score - Average score
Distance from the mean = 159 - 151
Distance from the mean = 8
Therefore, Pedro's practice exam score is 8 points above the average LSAT score. This distance is measured in the same units as the LSAT score, which are points. The standard deviation is not needed to calculate this distance, as we are only looking for the difference between Pedro's score and the average score, not the number of standard deviations away from the mean Pedro's score is.
