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On August 20, 1989, in Cologne, West Germany, Said Aouita of Morocco established a world record when he ran the 3000 m run in 7 minutes, 29.45 seconds. What was his average speed (in m/s) for the race?

Remember to include your data, equation, and work when solving the problem.

Answer :

Answer:

Average speed of Aouita = 6.68 meter per second.

Step-by-step explanation:

To create a world record Aouita ran a distance = 3000 m

He took the time to cover this distance = 7 minutes 29.45 seconds

= (7×60) + 29.45 seconds

= 449.45 seconds

Since, formula for the average speed is given by,

Average speed = [tex]\frac{\text{Total distance covered}}{\text{Total time taken}}[/tex]

Therefor, average speed of Aouita = [tex]\frac{3000}{449.45}[/tex]

= 6.675

≈ 6.68 meter per second

Average speed of Aouita was 6.68 meter per second.

Answer:

6.67 m/s

Step-by-step explanation:

7 * 60 = 420

420 + 29.45 = 449.45

V = 3000. / 449.45= 6.67 m/s

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