High School

Naturally occurring iridium has two isotopes: iridium-191 (190.9605940 amu) and iridium-193 (192.9629264 amu). The atomic mass of iridium is 192.22 amu.

What is the percent of iridium-193?

Answer :

Final answer:

We determine the percentage of iridium-193 in naturally occurring iridium by setting up an equation based on the weighted average atomic mass of iridium, using the masses of iridium-191 and iridium-193. By solving the equation, we find the proportion of iridium-193 which we can then express as a percentage.

Explanation:

To find the percentage of the isotope iridium-193, let's assume that the proportion of the isotope iridium-191 is x. Therefore, the proportion of iridium-193 would be (1-x). Given that the atomic mass of iridium is a weighted average of the mass of its isotopes, we can set up the following equation based on their atomic masses:

190.96059x + 192.96293(1-x) = 192.22

By solving this equation, we find the proportion of iridium-191 and subtract it from 1 to find the proportion of iridium-193. We then multiply the final result by 100 to express it as a percentage.

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