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------------------------------------------------ Multiply the polynomials:

[tex]\left(7x^2 + 9x + 7\right)(9x - 4)[/tex]

A. [tex]63x^3 + 53x^2 + 59x - 28[/tex]
B. [tex]63x^3 + 53x^2 + 27x - 28[/tex]
C. [tex]63x^3 + 81x^2 + 27x - 28[/tex]
D. [tex]63x^3 + 53x^2 + 27x + 28[/tex]

To solve the problem of multiplying the polynomials [tex]$(7x^2 + 9x + 7)(9x - 4)$[/tex], follow these steps:

1. Distribute each term in the first polynomial across each term in the second polynomial.

- Step 1: Multiply the first term in [tex]$(7x^2 + 9x + 7)$[/tex] by each term in [tex]$(9x - 4)$[/tex]:
- [tex]$7x^2 \cdot 9x = 63x^3$[/tex]
- [tex]$7x^2 \cdot (-4) = -28x^2$[/tex]

- Step 2: Multiply the second term in [tex]$(7x^2 + 9x + 7)$[/tex] by each term in [tex]$(9x - 4)$[/tex]:
- [tex]$9x \cdot 9x = 81x^2$[/tex]
- [tex]$9x \cdot (-4) = -36x$[/tex]

- Step 3: Multiply the third term in [tex]$(7x^2 + 9x + 7)$[/tex] by each term in [tex]$(9x - 4)$[/tex]:
- [tex]$7 \cdot 9x = 63x$[/tex]
- [tex]$7 \cdot (-4) = -28$[/tex]

2. Add all the resulting terms together:
- From the calculations, we have:
- [tex]$63x^3$[/tex]
- [tex]$-28x^2 + 81x^2 = 53x^2$[/tex]
- [tex]$-36x + 63x = 27x$[/tex]
- [tex]$-28$[/tex]

3. Combine like terms:
- The terms are already expanded and combined: [tex]$63x^3 + 53x^2 + 27x - 28$[/tex].

Based on these calculations, the correct answer is A: [tex]$63x^3 + 53x^2 + 27x - 28$[/tex].