College

Michael graphs the equations [tex]y = -\frac{1}{2} x + 4[/tex] and [tex]y = x + 1[/tex] to solve the equation [tex]-\frac{1}{2} x + 4 = x + 1[/tex].

What are the solution(s) of [tex]-\frac{1}{2} x + 4 = x + 1[/tex]?

Answer :

To solve the equation [tex]\(-\frac{1}{2}x + 4 = x + 1\)[/tex], we need to find the value of [tex]\(x\)[/tex] where the two equations [tex]\(y = -\frac{1}{2}x + 4\)[/tex] and [tex]\(y = x + 1\)[/tex] intersect.

Here's a step-by-step approach to solve it:

1. Start with the given equation:

[tex]\[
-\frac{1}{2}x + 4 = x + 1
\][/tex]

2. To eliminate the fraction, it's helpful to multiply the entire equation by 2 to make calculations easier:

[tex]\[
-x + 8 = 2x + 2
\][/tex]

3. To isolate [tex]\(x\)[/tex] on one side, add [tex]\(x\)[/tex] to both sides of the equation:

[tex]\[
8 = 3x + 2
\][/tex]

4. Next, subtract 2 from both sides to move the constant term to the other side:

[tex]\[
6 = 3x
\][/tex]

5. Finally, divide both sides by 3 to solve for [tex]\(x\)[/tex]:

[tex]\[
x = 2
\][/tex]

Therefore, the solution to the equation [tex]\(-\frac{1}{2}x + 4 = x + 1\)[/tex] is [tex]\(x = 2\)[/tex]. This means the two lines intersect at [tex]\(x = 2\)[/tex].