Answer :
Note that the maximum headwind needed to reach the final destination is given as 3.25m /s
How is this so?
Fuel consumption = TSFC x Thrust x flight time
Maximum flight time =
Maximum range / flight speed
= 3700000 / 280
= 13214.29 seconds
Fuel consumption
= 0.08 x 10,300 x 13214.29
= 10928.23 kg
Since the maximum fuel capacity is 4700 kg, the maximum fuel available for the flight would be 4700 kg.
Ground speed = flight speed - headwind
Range = ground speed x maximum flight time
Substituting the given values:
3700000 = (280 - headwind) x 13214.29
Solving for headwind:
280 - headwind = 3700000 / 13214.29
= 280 - (3700000 / 13214.29)
≈ 3.25 m/s
Hence the maximum headwind required to reach the destination is approximately 3.25 m/s.
Learn more about maximum headwind:
https://brainly.com/question/2994719
#SPJ1
