Answer :
Sure, let's solve the question about finding the next three terms of an exponential sequence where the first two terms are given as 18 and 6.
1. Identify the Known Values:
- First term ([tex]\(a_1\)[/tex]) = 18
- Second term ([tex]\(a_2\)[/tex]) = 6
2. Find the Common Ratio ([tex]\(r\)[/tex]):
- Since it is an exponential sequence, each term is found by multiplying the previous term by a constant, which is the common ratio.
- You can find [tex]\(r\)[/tex] using the formula for the second term:
[tex]\[
a_2 = a_1 \times r
\][/tex]
Substituting the known values:
[tex]\[
6 = 18 \times r
\][/tex]
- Solve for [tex]\(r\)[/tex]:
[tex]\[
r = \frac{6}{18} = \frac{1}{3}
\][/tex]
3. Calculate the Next Three Terms:
- Third term ([tex]\(a_3\)[/tex]):
[tex]\[
a_3 = a_2 \times r = 6 \times \frac{1}{3} = 2
\][/tex]
- Fourth term ([tex]\(a_4\)[/tex]):
[tex]\[
a_4 = a_3 \times r = 2 \times \frac{1}{3} = \frac{2}{3} \approx 0.67
\][/tex]
- Fifth term ([tex]\(a_5\)[/tex]):
[tex]\[
a_5 = a_4 \times r = \frac{2}{3} \times \frac{1}{3} = \frac{2}{9} \approx 0.22
\][/tex]
So the next three terms in the sequence are 2, approximately 0.67, and approximately 0.22.
1. Identify the Known Values:
- First term ([tex]\(a_1\)[/tex]) = 18
- Second term ([tex]\(a_2\)[/tex]) = 6
2. Find the Common Ratio ([tex]\(r\)[/tex]):
- Since it is an exponential sequence, each term is found by multiplying the previous term by a constant, which is the common ratio.
- You can find [tex]\(r\)[/tex] using the formula for the second term:
[tex]\[
a_2 = a_1 \times r
\][/tex]
Substituting the known values:
[tex]\[
6 = 18 \times r
\][/tex]
- Solve for [tex]\(r\)[/tex]:
[tex]\[
r = \frac{6}{18} = \frac{1}{3}
\][/tex]
3. Calculate the Next Three Terms:
- Third term ([tex]\(a_3\)[/tex]):
[tex]\[
a_3 = a_2 \times r = 6 \times \frac{1}{3} = 2
\][/tex]
- Fourth term ([tex]\(a_4\)[/tex]):
[tex]\[
a_4 = a_3 \times r = 2 \times \frac{1}{3} = \frac{2}{3} \approx 0.67
\][/tex]
- Fifth term ([tex]\(a_5\)[/tex]):
[tex]\[
a_5 = a_4 \times r = \frac{2}{3} \times \frac{1}{3} = \frac{2}{9} \approx 0.22
\][/tex]
So the next three terms in the sequence are 2, approximately 0.67, and approximately 0.22.