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------------------------------------------------ Mang Asyong sells sago in 4-kilo and 3-kilo containers. Due to high demand, he sold a total of 30 containers weighing 100 kilos. How many of each type did he sell?

To determine how many 4 kilo and 3 kilo sago containers Mang Asyong sold, we set up and solved a system of equations. The solution is that he sold 10 containers of 4 kilos and 20 containers of 3 kilos.

Explanation:

Mang Asyong sells sago in two container sizes: 4 kilos and 3 kilos. The problem states he sold 30 containers with a total weight of 100 kilos. To solve this, we can set up a system of equations and use algebra to find out how many of each type he sold. Let's denote the number of 4-kilo containers as x and the number of 3-kilo containers as y.

The first equation represents the total number of containers: x + y = 30.

The second equation represents the total weight of the containers: 4x + 3y = 100.

Solving these two equations simultaneously gives us the number of each type of container sold. Here are the steps:

Multiply the first equation by 3 to make the coefficients of y the same, yielding 3x + 3y = 90.
Subtract this new equation from the second equation:
4x + 3y (total weight)
-
3x + 3y (weighted number of containers)
=
x = 10.
To find y, we substitute x = 10 into the first equation: 10 + y = 30, so y = 20.

So, Mang Asyong sold 10 containers of 4 kilos and 20 containers of 3 kilos.