Answer :
Let the amount of the first bill be [tex]$x$[/tex]. According to the problem, the second bill is \[tex]$5 more than twice the first bill, which is expressed as:
$[/tex][tex]$
2x + 5
$[/tex][tex]$
Since the total of both bills is \$[/tex]157, we can set up the equation by adding the two amounts:
[tex]$$
x + (2x + 5) = 157
$$[/tex]
Combine like terms:
[tex]$$
3x + 5 = 157
$$[/tex]
Subtract 5 from both sides:
[tex]$$
3x = 157 - 5 = 152
$$[/tex]
Then, solving for [tex]$x$[/tex], we would divide both sides by 3:
[tex]$$
x = \frac{152}{3} \approx 50.67
$$[/tex]
Thus, the equation that represents the problem is:
[tex]$$
x + (2x + 5) = 157
$$[/tex]
This corresponds to option D.
$[/tex][tex]$
2x + 5
$[/tex][tex]$
Since the total of both bills is \$[/tex]157, we can set up the equation by adding the two amounts:
[tex]$$
x + (2x + 5) = 157
$$[/tex]
Combine like terms:
[tex]$$
3x + 5 = 157
$$[/tex]
Subtract 5 from both sides:
[tex]$$
3x = 157 - 5 = 152
$$[/tex]
Then, solving for [tex]$x$[/tex], we would divide both sides by 3:
[tex]$$
x = \frac{152}{3} \approx 50.67
$$[/tex]
Thus, the equation that represents the problem is:
[tex]$$
x + (2x + 5) = 157
$$[/tex]
This corresponds to option D.