High School

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------------------------------------------------ Let \( x = 2.7 \, \text{m} \), \( F = 46 \, \text{N} \), and \( \theta = 23^\circ \). What is the torque exerted by \( F \) about point \( P \) in Nm?

A. 28.3
B. 64.1
C. 38.5
D. 57.2

Answer :

Final answer:

The torque can be calculated using the formula au = rFsin( heta), but the computed torque of 121.443 Nm does not match any of the provided options.

The correct option is none of these.

Explanation:

To calculate the torque exerted by the force F about point P, the formula to use is au = rFsin( heta), where au is the torque in newton meters (Nm), r is the distance in meters from the point of rotation to the point where the force is applied, F is the force in newtons, and heta is the angle between the force and the distance vector.

Given that ( heta = 23 degrees), (r = 2.7 m), and (F = 46 N), the torque can be computed as follows:

au = (2.7 m) * (46 N) * sin(23 degrees) = 2.7 * 46 * 0.3907
= 121.443 Nm (where 0.3907 is the sine of 23 degrees)

The correct answer seems to be none of the options provided as a, b, c, or d.

The correct option is none of these.

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