High School

Lead has a specific heat capacity of approximately 128 J/kg·K. How much energy is required to raise the temperature of a 5 kg piece of lead from 40°C to 58°C? Express your answer in kilojoules.

Answer :

To find the energy required to raise the temperature of a 5 kg piece of lead from 40°C to 58°C, we can use the formula:

Energy = mass x specific heat capacity x temperature change

we need to calculate the temperature change. The initial temperature is 40°C, and the final temperature is 58°C. So the temperature change is:

Temperature change = Final temperature - Initial temperature
Temperature change = 58°C - 40°C
Temperature change = 18°C

we can plug in the values into the formula:

Energy = mass x specific heat capacity x temperature change
Energy = 5 kg x 128 J/kgK x 18°C

units for temperature change must match the units for specific heat capacity (K or Kelvin). To convert Celsius to Kelvin, we simply add 273 to the Celsius temperature:

Energy = 5 kg x 128 J/kgK x 18 K

Multiplying the numbers together, we get:

Energy = 115,200 J

To express the answer in kilojoules, we divide by 1000:

Energy = 115.2 kJ
the energy required to raise the temperature of a 5 kg piece of lead from 40°C to 58°C is approximately 115.2 kilojoules.

To know more about specific heat capacity:

https://brainly.in/question/1236607

#SPJ11