High School

Ken and Susie are standing together. Ken walks 10 m [N] and then 15 m [W]. Susie walks 25 m [E] and then 30 m [S]. What is the displacement from Ken to Susie?

Answer :

Final answer:

To find the displacement from Ken to Susie, we need to subtract Ken's displacement from Susie's. The final displacement from Ken to Susie is 40 m [E] and 40 m [S]. This means that Susie is 40 meters to the East and 40 meters to the South of Ken's final position.

Explanation:

In this problem, we first need to calculate the displacement for both individuals. Displacement refers to the shortest distance between the initial and the final point, and it has both magnitude and direction.

Ken walks 10 m [N] and then 15 m [W]. So his displacement is 10 m North and 15 m West.

Susie, on the other hand, walks 25 m [E] and then 30 m [S]. So her displacement is 25 m East and 30m South.

Now, to determine the displacement from Ken to Susie, we subtract Ken's displacement from Susie's.

East-West, Susie is 25 m (East) and Ken is -15 m (West). Therefore, the displacement in the East-West direction is 25 m - (-15 m) = 40 m [E].

North-South: Susie and Ken are both -30 m (South) and 10 m (North) respectively. Therefore, the North-South displacement is -30 m - 10 m = -40 m [S].

By convention, Eastward displacement is positive and Westward is negative. Likewise, Northward displacement is positive and Southward is negative. So the final displacement from Ken to Susie is 40 m [E] and 40 m [S].

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