College

Karissa begins to solve the equation [tex]\frac{1}{2}(x-14)+11=\frac{1}{2} x-(x-4)[/tex]. Her work is shown below:

[tex]
\begin{array}{l}
\frac{1}{2}(x-14)+11=\frac{1}{2} x-(x-4) \\
\frac{1}{2} x-7+11=\frac{1}{2} x-x+4 \\
\frac{1}{2} x+4=-\frac{1}{2} x+4
\end{array}
[/tex]

When she subtracts 4 from both sides, [tex]\frac{1}{2} x=-\frac{1}{2} x[/tex] results. What is the value of [tex]x[/tex]?

A. [tex]-1[/tex]
B. [tex]\frac{1}{2}[/tex]
C. [tex]0[/tex]
D. [tex]\frac{1}{2}[/tex]

Answer :

Let's solve the equation step by step to find the value of [tex]\( x \)[/tex].

We start with the following equation:

[tex]\[
\frac{1}{2}(x-14) + 11 = \frac{1}{2}x - (x-4)
\][/tex]

1. Distribute [tex]\(\frac{1}{2}\)[/tex] into [tex]\((x-14)\)[/tex]:

[tex]\[
\frac{1}{2}x - 7 + 11 = \frac{1}{2}x - x + 4
\][/tex]

2. Simplify both sides:

- On the left side, combine [tex]\(-7\)[/tex] and [tex]\(11\)[/tex]:

[tex]\[
\frac{1}{2}x + 4
\][/tex]

- On the right side, combine like terms:

[tex]\[
-\frac{1}{2}x + 4
\][/tex]

So, we now have:

[tex]\[
\frac{1}{2}x + 4 = -\frac{1}{2}x + 4
\][/tex]

3. Subtract [tex]\(4\)[/tex] from both sides:

This simplifies to:

[tex]\[
\frac{1}{2}x = -\frac{1}{2}x
\][/tex]

4. Add [tex]\(\frac{1}{2}x\)[/tex] to both sides:

[tex]\[
\frac{1}{2}x + \frac{1}{2}x = 0
\][/tex]

5. Combine like terms:

[tex]\[
x = 0
\][/tex]

The value of [tex]\( x \)[/tex] is [tex]\( 0 \)[/tex].