Answer :
To solve the problem, we need to set up an equation to find the total number of pages, [tex]\( p \)[/tex], in the novel based on the information given.
1. Understanding the Problem:
- John read 114 pages, which is 3 pages less than one-third of the entire novel.
2. Setting Up the Equation:
- We know that 114 pages are 3 pages less than [tex]\(\frac{1}{3}\)[/tex] of the total pages. This can be expressed in equation form as:
[tex]\[
114 = \frac{1}{3}p - 3
\][/tex]
3. Solving the Equation:
- First, add 3 to both sides of the equation to eliminate the '-3':
[tex]\[
114 + 3 = \frac{1}{3}p
\][/tex]
[tex]\[
117 = \frac{1}{3}p
\][/tex]
- Next, solve for [tex]\( p \)[/tex] by multiplying both sides by 3 to cancel the fraction:
[tex]\[
p = 117 \times 3
\][/tex]
[tex]\[
p = 351
\][/tex]
Thus, the equation [tex]\( 117 = \frac{1}{3}p \)[/tex] best describes the situation, and the total number of pages in the novel is 351.
1. Understanding the Problem:
- John read 114 pages, which is 3 pages less than one-third of the entire novel.
2. Setting Up the Equation:
- We know that 114 pages are 3 pages less than [tex]\(\frac{1}{3}\)[/tex] of the total pages. This can be expressed in equation form as:
[tex]\[
114 = \frac{1}{3}p - 3
\][/tex]
3. Solving the Equation:
- First, add 3 to both sides of the equation to eliminate the '-3':
[tex]\[
114 + 3 = \frac{1}{3}p
\][/tex]
[tex]\[
117 = \frac{1}{3}p
\][/tex]
- Next, solve for [tex]\( p \)[/tex] by multiplying both sides by 3 to cancel the fraction:
[tex]\[
p = 117 \times 3
\][/tex]
[tex]\[
p = 351
\][/tex]
Thus, the equation [tex]\( 117 = \frac{1}{3}p \)[/tex] best describes the situation, and the total number of pages in the novel is 351.
