High School

Jodi, Anna, and Susie had $42 between them. Jodi had twice as much as Anna, who had twice as much as Susie. Which girl had $12?

A. Jodi
B. Anna
C. Susie
D. None of them had $12.

Answer :

Final answer:

Jodi, Anna, and Susie had a total of $42. Anna had $12.

Explanation:

In this problem, we are given that Jodi, Anna, and Susie had a total of $42. Additionally, we are given that Jodi had twice as much as Anna and Anna had twice as much as Susie. We are asked which girl had $12.

Let's assign variables:

  • J = amount of money Jodi had
  • A = amount of money Anna had
  • S = amount of money Susie had

From the problem, we can set up these equations:

  1. J = 2A
  2. A = 2S
  3. J + A + S = 42

Substituting the second equation into the first equation, we get J = 2(2S) = 4S. Substituting J = 4S and A = 2S into the third equation, we have 4S + 2S + S = 42. Simplifying the equation, we get 7S = 42, which means S = 6.

Therefore, Susie had $6. Since Anna had twice as much as Susie, Anna had $6 x 2 = $12. Thus, Anna had $12.

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