College

Jessica burns a total of 480 calories during her workout at the gym. She lifts weights and then walks on the treadmill for 30 minutes. Jessica burns 150 calories lifting weights. She burns [tex]$c$[/tex] calories for each minute she walks.

Which equation represents this situation?

A. [tex]$150 - 30c = 480$[/tex]

B. [tex]$(150 + 30)c = 480$[/tex]

C. [tex]$150c + 30 = 480$[/tex]

D. [tex]$150 + 30c = 480$[/tex]

Answer :

To solve this problem, we need to understand how many calories Jessica burns during her workout and how this relates to the equation options given.

Here's the breakdown:

1. Total Calories Burned: Jessica burns 480 calories during the entire workout.

2. Calories Burned Lifting Weights: She burns 150 calories lifting weights.

3. Calories Burned Walking: She walks on the treadmill for 30 minutes, burning [tex]\( c \)[/tex] calories per minute.

4. Equation Setup:

- The calories burned from walking can be represented as [tex]\( 30c \)[/tex] because she walks for 30 minutes and burns [tex]\( c \)[/tex] calories per minute.

- The total calories burned is the sum of calories burned lifting weights and calories burned walking. Therefore, the equation representing this situation is:

[tex]\[
150 + 30c = 480
\][/tex]

This equation sums the calories burned lifting weights (150) with the calories burned walking ([tex]\( 30c \)[/tex]) to equal the total calories burned (480).

So, the correct equation that represents the situation is [tex]\( 150 + 30c = 480 \)[/tex].