High School

Jerald jumped from a bungee tower. If the equation that models his height, in feet, is [tex] h = -16t^2 + 729 [/tex], where [tex] t [/tex] is the time in seconds, for which interval of time is he less than 104 feet above the ground?

A. [tex] t \gt 6.25 [/tex]

B. [tex] -6.25 \lt t \lt 6.25 [/tex]

C. [tex] t \lt 6.25 [/tex]

D. [tex] 0 \leq t \leq 6.25 [/tex]

Answer :

To determine when Jerald is less than 104 feet above the ground, we start with the equation that models his height:

[tex]\[ h = -16t^2 + 729 \][/tex]

We want to find out for what time [tex]\( t \)[/tex] this height [tex]\( h \)[/tex] is less than 104 feet:

[tex]\[ -16t^2 + 729 < 104 \][/tex]

First, solve the inequality for when the height is exactly 104 feet:

[tex]\[ -16t^2 + 729 = 104 \][/tex]

Subtract 104 from both sides:

[tex]\[ -16t^2 + 729 - 104 = 0 \][/tex]

Simplify the equation:

[tex]\[ -16t^2 + 625 = 0 \][/tex]

Add 16t^2 to both sides to isolate t:

[tex]\[ 16t^2 = 625 \][/tex]

Now, divide by 16:

[tex]\[ t^2 = \frac{625}{16} \][/tex]

Taking the square root of both sides:

[tex]\[ t = \pm\sqrt{\frac{625}{16}} \][/tex]

Calculating the square root:

[tex]\[ t = \pm\frac{25}{4} \][/tex]

These are the critical points: [tex]\( t = -\frac{25}{4} \)[/tex] and [tex]\( t = \frac{25}{4} \)[/tex].

Since time [tex]\( t \)[/tex] must be positive (as it represents time starting from the jump), we'll focus on the positive critical point:

[tex]\[ t = \frac{25}{4} = 6.25 \][/tex]

So, Jerald is less than 104 feet above the ground between these critical points. Therefore, the interval of time when Jerald is less than 104 feet above the ground is:

[tex]\[ 0 < t < 6.25 \][/tex]

This aligns with the given option:

[tex]\(0 \leq t \leq 6.25\)[/tex]