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JC is 67 kg male receiving Bactrim 80mg/16mg IV (sulfamethoxazole/trimethoprim) for Listeria spp. meningitis. The doctor orders 5 mg/kg of trimethoprim every 6 hours. How much sulfamethoxazole will the patient receive per day?

Answer :

The patient will receive approximately 67 mg of sulfamethoxazole per day.

To calculate the amount of sulfamethoxazole the patient will receive per day, we need to determine the dosage based on the patient's weight and the prescribed dosage per kilogram.

The patient's weight is given as 67 kg. The prescribed dosage is 5 mg/kg of trimethoprim every 6 hours. Since the Bactrim formulation contains sulfamethoxazole and trimethoprim in a fixed ratio of 80mg/16mg, we need to convert the trimethoprim dosage to sulfamethoxazole.

First, we calculate the total dosage of trimethoprim per day:

Dosage per day = (Dosage per kilogram) × (Patient's weight)

= 5 mg/kg × 67 kg

= 335 mg

Since the Bactrim formulation has a 1:5 ratio of trimethoprim to sulfamethoxazole, the dosage of sulfamethoxazole will be one-fifth of the total trimethoprim dosage:

Sulfamethoxazole dosage per day = (Trimethoprim dosage per day) ÷ 5

= 335 mg ÷ 5

= 67 mg

Therefore, the patient will receive approximately 67 mg of sulfamethoxazole per day.

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